map reduce filter in python

 Map,reduce,filter

lis = ["1","2","3","4","5","5"]

# sabse pahile maine int me convert kiya hai isko uske baad usko hamne add kiya hai .... but same kaam haam map function se kar sakte hai

lis = list(map(int,lis))

# for i in range(len(lis)):

#     lis[i] = int(lis[i])

# agar apko squre nikalne hai kisis list ke item ke to aap usko nikal sakte ho

lis_num = [1,2,2,4,5,6,7,8,9,0,0,77,7,5]

square_using_lambda = list(map(lambda x : x*x,lis_num))

# dusra hota hai ki aap function banakar use kar sakte hai

def squr(x):

    return x*x

# isse aap function call karke nikal sakte ho

# print(list(map(squr,lis_num)))

def sq(x):

    return x*x

def cube(x):

    return x*x*x

lis_number = [sq,cube]

for i in range(5):

    val = list(map(lambda x:x(i),lis_number))

    # print(val)

# filter function in the python

li = [1,2,3,4,5,6,7,8,9,0,56]

def num_greter_than_2(x):

    return x>2

f = list(filter(num_greter_than_2,li))

# print(f)

import functools as t

list3 = [1,2,3,4,5]

# agar apko iske total sub dekhni hogi to aap isko loop me chala kar add karenge

# num = 0

# for i in list3:

#     num = num+i

# but iske alava bhi iski sum kar sakte hai

num = t.reduce(lambda x,y:x*y,list3)

print(num)